How do you solve the following system: $4x-5y= -1, 2x+9y=5$ ?

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Answer 1 · 2018-03-09T05:58:17

$x= 8/23 , y=11/23$

$4x-5y=-1$ [A]
$2x+9y=5$ [B}

$2xx$ [B] -> $4x+18y=10$ [C]

[C] - [A] $-> 23y=11$

$:. y =11/23$

$y=11/23$ in [B] $-> 2x +9xx11/23 =5$

$x = 1/2(5-99/23)$

$= 1/2 xx 16/23 = 8/23$

How do you solve the following system: 4x-5y= -1, 2x+9y=5 4x-5y= -1, 2x+9y=5 ?