How do you solve the following system: $5 x + 8 y = - 29, 8 x - 7 y = - 39$ $5x+8y= -29, 8x-7y=-39$ ?

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How do you solve the following system: $5 x + 8 y = - 29, 8 x - 7 y = - 39$ $5x+8y= -29, 8x-7y=-39$ ?

1 Answer

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Answer 1 · 2016-03-26T11:07:55

$x = - \frac{515}{99}; y = - \frac{37}{99}$ $x= -515/99 ; y=-37/99$

Explanation:

$5 x + 8 y = - 29$ $5x+8y = -29$ (1)
$8 x - 7 y = - 39$ $8x-7y = -39$ (2)
Multplying equation (1) by 8 and Equation (2) by 5 we get;
$40 x + 64 y = - 232$ $40x+64y = -232$ (1)
$40 x - 35 y = - 195$ $40x-35y = -195$ (2); Now subtracting (2)from (1) we get $99 y = - 37 or y = - \frac{37}{99};$ $99y= -37 or y=-37/99;$ Putting y=37/99 in equation(1) we get $x = - \frac{515}{99}$ $x=-515/99$ [Ans]

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How do you solve the following system: $5 x + 8 y = - 29, 8 x - 7 y = - 39$ $5x+8y= -29, 8x-7y=-39$ ?

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

How do you solve the following system: 5x+8y=−29,8x−7y=−39 5x+8y= -29, 8x-7y=-39 ?

1 Answer

Explanation:

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Impact of this question

How do you solve the following system: $5 x + 8 y = - 29, 8 x - 7 y = - 39$ $5x+8y= -29, 8x-7y=-39$ ?