How do you solve the following system: $6x + y = 2, 2x + 3y = 34$ ?

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Answer 1 · 2018-03-25T00:08:18

$x=-7/4$
$y= 25/2$

Solve using substitution:
$6x+y=2$
$2x+3y= 34$

The first equation when solved for $y$ :
$y=-6x+2$

Substitute for $y$ into the second equation:
$2x+3(-6x+2)= 34$

Distribute:
$2x-18x+6= 34$

Combine like terms:
$-16x+6= 34$

Solve for x:
$-16x=28$
$x=28/-16$
$x=-7/4$

Solve for y by plugging in for $x$ :
$y=-6(-7/4)+2$
$y= 42/4+2$
$y= 21/2+4/2$
$y= 25/2$

How do you solve the following system: 6x + y = 2, 2x + 3y = 346x + y = 2, 2x + 3y = 34?