How do you solve the following system: $x + 3 y = - 2, 6 x + 7 y = - 9$ $x+3y=-2, 6x + 7y = -9$ ?

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Answer 1 · 2018-03-05T18:46:16

$x + 3 y = - 2$ $x + 3y = -2$
$6 x + 7 y = - 9$ $6x + 7y = -9$

multiply first equation by 6 -> $6 x + 18 y = - 12$ $6x + 18y = -12$

subtract the two equations to end up with: $11 y = - 21$ $11y = -21$

After subtracting the two equations:

Solve for y then substitute it into one of either equations and find the value of x.

How do you solve the following system: x+3y=-2, 6x + 7y = -9 x+3y=−2,6x+7y=−9x+3y=-2, 6x + 7y = -9 ?