How do you solve the inequality $x^{2} < 10 x - 25$ $x^2<10x-25$ ?

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Answer 1 · 2017-01-25T14:00:06

The solution is $S = {\emptyset}$ $S={O/}$

Let's factorise the inequality

$x^{2} < 10 x - 25$ $x^2<10x-25$

$x^{2} - 10 x + 25 < 0$ $x^2-10x+25<0$

$(x - 5) (x - 5) < 0$ $(x-5)(x-5)<0$

${(x - 5)}^{2} < 0$ $(x-5)^2<0$

$AA x in RR,$ $=>$ , $(x-5)^2>=0$

Therefore,

There is no solution

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