How do you solve the inequality $x^2+12x<-36$ ?

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Answer 1 · 2016-11-06T07:00:50

No solution.

$x^2+12x<-36$

$hArrx^2+12x+36<0$

or $x^2+2xx6xx x+6^2<0$

or $(x+6)^2<0$

But we cannot have $(x+6)^2<0$ , as $(x+6)^2$ is always positive.

Hence, we have no solution.

How do you solve the inequality x^2+12x<-36x^2+12x<-36?