Question

How do you solve the quadratic using the quadratic formula given `b^2-7b-3=0` over the set of complex numbers?

Answer 1

`x = 7/2 +- sqrt(61)/2` The answer is not complex

Explanation:

Quadratic formula when using `Ax^2 + Bx +C = 0`:

`x = (-B +- sqrt(B^2 - 4AC))/(2A)`

`x = (7 +- sqrt(49 - 4(1)(-3)))/(2(1)) = (7 +- sqrt(61))/2 = 7/2 +- sqrt(61)/2`