How do you solve the quadratic $x^{2} - 2 x + 1 = 0$ $x^2-2x+1=0$ using any method?

Question

2004 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-14T12:56:25

$x = 1$ $x=1$

I will use factorization:

$x^{2} - 2 x + 1 = 0$ $x^2-2x+1=0$

$0 = (x - 1) (x - 1)$ $0=(x-1)(x-1)$

Thus we have a repeated root (one solution) for the answer to this quadratic:

$x = 1$ $x=1$

How do you solve the quadratic x2−2x+1=0x^2-2x+1=0 using any method?