How do you solve the right triangle ABC if b=120m, A=12?

1 Answer
Mar 26, 2018

#color(maroon)("Case 1 : "#
#color(indigo)(a = 24.95m,hatB = 90^@, hatC = 78^@, c = 117.38m, A_t = 1464.32 " sq m"#

#color(green)("Case 2 : "#
#color(green)(a = 25.51m, hatB = 78^@, hatC = 90^@, c = 122.68m, A_t = 1530.6 " sq m"#

Explanation:

Case 1 :

#b = 120 m, hat B = 90^@, hat A = 12^@#

#hat C = 180 - 90 - 12 = 78^@#

Applying the Law of Sines,

#a / sin A = B / sin B = c ? sin C#

#a = (120 * sin 12) / sin 90 = 24.95 " m"#

#c = (120 * sin 78) / sin 90 = 117.38 " m"#

#"Area of rt triangle " A_t = (1/2) * a * c = (1/2) * 24.95 * 117.38 = color(indigo)(1464.32 " sq m"#

Case 2 :

#b = 120 m, hat A = 12^@, hat A = 90^@#

#hat B = 180 - 12 - 90 = 78^@#

#color(green)("Applying the Law of Sines,"#

#a / sin A = b / sin B = c / sin C#

#a = (b*sin A) / sin B = (120 * sin 12) / sin 78 = 25.51 " m"#

#"Applying Pythagoras theorem,"#

#c = sqrt(a^2 + b^2) = sqr(25.51^2 + 120^2) = 122.68 " m"#

#"Area of rt triangle "A_t = (1/2) * a * b = (1/2) * 25.51 * 120 = color(green)(1530.6 " sq m"#