How do you solve the right triangle given a = 11cm, b = 26cm?

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Answer 1 · 2018-05-08T02:53:29

#c = sqrt{797}#

#C=90^circ#

#B = text{Arc}text{tan}(26/11) #

#A = text{Arc}text{tan}(11/26) #

If it's a right triangle, we have

#c^2=a^2+b^2= 11^2+26^2=797#

#c = sqrt{797}#

We have

#C=90^circ#

# tan B = b/a = 26/11 #

#B = text{Arc}text{tan}(26/11) #

We want the principal value in the first quadrant.

#tan A = a/b = 11/26#

#A = 90^circ - B = text{Arc}text{tan}(11/26) #

I'll leave the calculator to you.