How do you solve the system a+b=11 and 3a-2b=8?
1 Answer
Jul 31, 2018
Explanation:
a+b=11to(1)
3a-2b=8to(2)
"from equation "(1)color(white)(x)a=11-bto(3)
"substitute "a=11-b" into equation "(2)
3(11-b)-2b=8
33-3b-2b=8
33-5b=8
"subtract 33 from both sides"
-5b=8-33=-25
"divide both sides by "-5
b=(-25)/(-5)=5
"substitute "b=5" into equation "(3)
a=11-5=6
"solution is "(a,b)to(6,5)