How do you solve the system a+b=11 and 3a-2b=8?

1 Answer
Jul 31, 2018

(a,b)to(6,5)

Explanation:

a+b=11to(1)

3a-2b=8to(2)

"from equation "(1)color(white)(x)a=11-bto(3)

"substitute "a=11-b" into equation "(2)

3(11-b)-2b=8

33-3b-2b=8

33-5b=8

"subtract 33 from both sides"

-5b=8-33=-25

"divide both sides by "-5

b=(-25)/(-5)=5

"substitute "b=5" into equation "(3)

a=11-5=6

"solution is "(a,b)to(6,5)