How do you solve the system of equations $3 x - y = 14$ $3x - y = 14$ and $2 x + y = 11$ $2x + y = 11$ ?

Question

4631 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-18T12:41:51

$x = 5$ $x=5$ and $y = 1$ $y=1$

After summing 2 equation for eliminating $y$ $y$ ,

$3 x - y + 2 x + y = 14 + 11$ $3x-y+2x+y=14+11$

$5 x = 25$ $5x=25$ , so $x = 5$ $x=5$

Hence, $2 \cdot 5 + y = 11$ $2*5+y=11$ or $10 + y = 11$ $10+y=11$ . Thus $y = 1$ $y=1$

How do you solve the system of equations 3x−y=143x - y = 14 and 2x+y=112x + y = 11?