How do you solve the system of equations -4x + 4y = 44x+4y=4 and y = 9x + 73y=9x+73?

1 Answer
Mar 20, 2018

See a solution process below:

Explanation:

Step 1) Solve the first equation for xx:

-4x + 4y = 44x+4y=4

-4x + 4y - color(red)(4y) = 4 - color(red)(4y)4x+4y4y=44y

-4x + 0 = 4 - 4y4x+0=44y

-4x = 4 - 4y4x=44y

(-4x)/color(red)(-4) = (4 - 4y)/color(red)(-4)4x4=44y4

x = 4/color(red)(-4) - (4y)/color(red)(-4)x=444y4

x = -1 + yx=1+y

Step 2) Substitute (-1 + y)(1+y) for xx in the second equation and solve for yy:

y = 9x + 73y=9x+73 becomes:

y = 9(-1 + y) + 73y=9(1+y)+73

y = (9 * -1) + (9 * y) + 73y=(91)+(9y)+73

y = -9 + 9y + 73y=9+9y+73

y - color(red)(9y) = -9 + 9y - color(red)(9y) + 73y9y=9+9y9y+73

1y - color(red)(9y) = -9 + 0 + 731y9y=9+0+73

(1 - color(red)(9))y = -9 + 73(19)y=9+73

-8y = 648y=64

(-8y)/color(red)(-8) = 64/color(red)(-8)8y8=648

y = -8y=8

Step 3) Substitute -88 for yy in the solution to the first equation at the end of Step 1 and calculate xx:

x = -1 + yx=1+y becomes:

x = -1 + (-8)x=1+(8)

x = -1 - 8x=18

x = -9x=9

The Solution Is:

x = -9x=9 and y = -8y=8

Or

(-9, -8)(9,8)