How do you solve the system of equations $x - y = 2$ $x- y = 2$ and $3 x - 3 y = 1$ $3x - 3y = 1$ ?

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How do you solve the system of equations $x - y = 2$ $x- y = 2$ and $3 x - 3 y = 1$ $3x - 3y = 1$ ?

1 Answer

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Answer 1 · 2018-04-24T09:24:17

It cannot be solved.

Explanation:

$x - y = 2$ $x-y=2$
$3 x - 3 y = 1$ $3x-3y=1$

$So, from the second equation, x - y = 1$ $"So, from the second equation", x-y=1$
$This is not the same as the first equation, which states x - y = 2$ $"This is not the same as the first equation, which states " x-y=2$

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How do you solve the system of equations $x - y = 2$ $x- y = 2$ and $3 x - 3 y = 1$ $3x - 3y = 1$ ?

1 Answer

Explanation:

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How do you solve the system of equations x- y = 2x−y=2x- y = 2 and 3x - 3y = 13x−3y=13x - 3y = 1?

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How do you solve the system of equations $x - y = 2$ $x- y = 2$ and $3 x - 3 y = 1$ $3x - 3y = 1$ ?