How do you solve the triangle given B=75^circ20', a=6.2, c=9.5?

1 Answer
May 27, 2017

angleB=14°40',angleA=75°20',b=1.623

Explanation:

angle B in the question should be angle A

angleA=75°20',a=6.2,c=9.5

:.Ajacent/opposite=b/a= Cot 75°20'

:.b/6.2= Cot 75°20'

multiply both sides by 6.2

:.b=Cot 75°20' xx 6.2

:.b=0.261723366 xx 6.2

:.b=1.622684873

:.color(blue)(b=1.623 to the nearest 3 decimal places.

:.180°-(90°+75°20')=14°40'

:.color(blue)(angleB=14°40'