How do you solve this system of equations using substitution?

Question

$y=-8x$
$2x+4y=0$

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Answer 1 · 2017-03-14T05:50:41

$x=0, y=0.$

$because, y=-8x,$ we substitute $-8x for y$ in $2x+4y=0$ & get,

$2x+4(-8x)=0 rArr 2x-32x=0 rArr -30x=0 rArr x=0/-30=0.$

Accordingly, $y=-8x=-8(0)=0.$

Thus, $x=0, y=0$ is a Soln.

Also, these roots satisfy the given eqns.

Hence, the soln. $x=0, y=0.$

Enjoy Maths.!