How do you solve this system of equations: $y= 2x - 7 , 3x + y = 8$ ?

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Answer 1 · 2018-06-25T23:14:39

$(3,-1)$

We already have $y$ solved for in terms of $x$ , so we can plug this value into the second equation. This gives us

$3x+color(steelblue)(2x-7)=8$

Note that what I have in blue is $y$ . This simplifies to

$5x-7=8$

Adding $7$ to both sides gives us

$5x=15$

Dividing both sides by $5$ , we get

$color(blue)(x=3)$

To solve for $y$ , we can plug this value of $x$ into the first equation

$y=2x-7$

$y=2(3)-7=6-7=color(steelblue)(-1)$

The solution of these two equations is at the point

$(3,-1)$

Hope this helps!

How do you solve this system of equations: y= 2x - 7 , 3x + y = 8y= 2x - 7 , 3x + y = 8?