How do you solve using elimination of $-2x=6y+18$ and $-29=5y-3x$ ?

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Answer 1 · 2018-07-11T20:29:52

$x=3,y=-4$

Dividing the first equation by #-2' we get

$x=-3y-9$
substituting this )for $y$ in the second equation we get

$5y-3(-3y-9)=-29$

expanding we get

$5y+9y+27=29$

combining like Terms and adding $-27$

so we get

$14y=-56$

so we get

$y=-4$

How do you solve using elimination of -2x=6y+18-2x=6y+18 and -29=5y-3x-29=5y-3x?