How do you solve using elimination of $3 x = 10 - 2 y$ $3x=10-2y$ and $5 x - 6 y + 30 = 0$ $5x-6y+30=0$ ?

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How do you solve using elimination of $3 x = 10 - 2 y$ $3x=10-2y$ and $5 x - 6 y + 30 = 0$ $5x-6y+30=0$ ?

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Answer 1 · 2018-06-13T15:22:32

$x = 0$ $x=0$
$y = 5$ $y=5$

Explanation:

$3 x = 10 - 2 y$ $3x=10-2y$ --- (1)
$5 x - 6 y + 30 = 0$ $5x-6y+30=0$ --- (2)

From (1)
$3 x = 10 - 2 y$ $3x=10-2y$
$x = \frac{1}{3} (10 - 2 y)$ $x=1/3(10-2y)$ --- (3)

Sub (3) into (2)
$5 \times \frac{1}{3} (10 - 2 y) - 6 y + 30 = 0$ $5times1/3(10-2y)-6y+30=0$
$\frac{5}{3} (10 - 2 y) - 6 y + 30 = 0$ $5/3(10-2y)-6y+30=0$
$\frac{50}{3} - \frac{10}{3} y - 6 y + 30 = 0$ $50/3-10/3y-6y+30=0$
$\frac{140}{3} - \frac{28}{3} y = 0$ $140/3-28/3y=0$
$140 - 28 y = 0$ $140-28y=0$
$140 = 28 y$ $140=28y$
$y = 5$ $y=5$ --- (4)

Sub (4) into (3)
$x = \frac{1}{3} (10 - 2 y)$ $x=1/3(10-2y)$
$x = \frac{1}{3} (10 - 10)$ $x=1/3(10-10)$
$x = 0$ $x=0$

Answer 2 · 2018-06-13T15:24:05

$x = 0, y = 5$ $x=0,y=5$

Explanation:

Multiplying the first equation by $3$ $3$ and adding to the second we get
$14 x = 0$ $14x=0$
so
$x = 0$ $x=0$
with this result we get
$y = 5$ $y=5$

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How do you solve using elimination of $3 x = 10 - 2 y$ $3x=10-2y$ and $5 x - 6 y + 30 = 0$ $5x-6y+30=0$ ?

2 Answers

Explanation:

Explanation:

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How do you solve using elimination of 3x=10−2y3x=10-2y and 5x−6y+30=05x-6y+30=0?

2 Answers

Explanation:

Explanation:

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How do you solve using elimination of $3 x = 10 - 2 y$ $3x=10-2y$ and $5 x - 6 y + 30 = 0$ $5x-6y+30=0$ ?