How do you solve using elimination of $x-y=-3$ and $5x+3y=1$ ?

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Answer 1 · 2018-03-28T12:34:01

$color(blue)(x=-1)$

$color(blue)(y=2)$

$x-y=-3\ \ \ \ \ [1]$

$5x+3y=1\ \ \ \ \ \ \ [2]$

Multiply $[1]$ by 5:

$5x-5y=-15\ \ \ \ \ [3]$

Subtract $[2]$ from $[3]$ :

$5x-5y=-15$

$5x+3y=1$

$0-8y=-16$

Divide by $-8$

$y=(-16)/-8=2$

Substitute this is $[1]$

$x-(2)=-3$

Add 2 to both sides:

$x=-1$

Solution:

$color(blue)(x=-1)$

$color(blue)(y=2)$

How do you solve using elimination of x-y=-3x-y=-3 and 5x+3y=15x+3y=1?