How do you solve (x+1)(x-3)>0(x+1)(x3)>0?

1 Answer
Oct 26, 2016

Please see the explanation.

Explanation:

Look at #(x + 1)(x - 3) = 0

This means that the function is 0 at x = -1 and x = 3x=1andx=3.

Also, it means that the sign of the corresponding factor changes sign at that value of x.

At values of x < -1:

Both (x + 1)(x+1) and (x - 3)(x3) are negative. A negative multiplied by a negative is a positive, therefore, x < -1 is one of the regions where (x + 1)(x - 3) > 0(x+1)(x3)>0. Let's make a note of that:

x < -1x<1

At values between -1 and 3:

(x + 1)(x+1) is positive but (x -3)(x3) is still negative. A positive multiplied by a negative is negative, therefore, this is NOT a region for (x + 1)(x - 3) >0(x+1)(x3)>0

At values x > 3x>3:

Both (x + 1)(x+1) and (x - 3)(x3) are positive. A positive multiplied by a positive is a positive, therefore, x > 3 is one of the regions where #(x + 1)(x - 3) > 0. Let's make a note of that:

x < -1 and x > 3x<1andx>3

We have no more regions to investigate, therefore, the above is our answer.