How do you solve $x^{\frac{2}{3}} = (\frac{1}{8})$ $x^(2/3)=(1/8)$ ?

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Answer 1 · 2016-01-10T18:44:42

Start by raising both sides of the equation to the $\frac{3}{2}$ $3/2$ power ...

$x^{\frac{2}{3}} = (\frac{1}{8})$ $x^(2/3)=(1/8)$

${[x^{\frac{2}{3}}]}^{\frac{3}{2}} = {[(\frac{1}{8})]}^{\frac{3}{2}}$ $[x^(2/3)]^(3/2)=[(1/8)]^(3/2)$

Now simplify ...

$x = \pm \frac{1}{\sqrt{8^{3}}} = \pm \frac{1}{16 \sqrt{2}} = \pm \frac{\sqrt{2}}{32}$ $x=+-1/sqrt(8^3)=+-1/(16sqrt2)=+-sqrt2/32$

hope that helped

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