How do you solve $x^{2} - 6 x + 9 < 0$ $x^2-6x+9<0$ using a sign chart?

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Answer 1 · 2017-02-02T06:46:34

The solution is $S = {\emptyset}$ $S={O/}$

Let's factorise the LHS

$x^{2} - 6 x + 9 = (x - 3) (x - 3) = {(x - 3)}^{2}$ $x^2-6x+9=(x-3)(x-3)=(x-3)^2$

Let $f (x) = {(x - 3)}^{2}$ $f(x)=(x-3)^2$

$x^{2} - 6 x + 9 < 0$ $x^2-6x+9<0$

This is impossible since

$AA x in RR, f(x)>0$

How do you solve x^2-6x+9<0x2−6x+9<0x^2-6x+9<0 using a sign chart?