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How do you solve $x^{2} - 9 x + 8 > 0$ $x^2-9x+8>0$ ?

1 Answer

Dec 4, 2016

$x > 8 or x > 1$ $x > 8 or x > 1$

Explanation:

$x^{2} - 9 x + 8 > 0 \to$ $x^2 - 9x + 8 > 0 to$

$(x - 8) (x - 1) > 0$ $(x-8)(x-1) > 0$

$x > 8 or x > 1$ $x > 8 or x > 1$

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