How do you solve $(x/3) = (12/(x-5))$ ?

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Answer 1 · 2015-04-06T21:03:16

Cross-multiply:
$x^2 - 5x = 36$
$x^2-5x-36=0$
$(x-9)(x+4) = 0$
$x=9; x=-4$

To check:
$(9/3) =(12/(9-5))$
$3 = 3$

$(-4/3) = (12/(-4-5))$
$(-4/3) = -4/3$

How do you solve (x/3) = (12/(x-5))(x/3) = (12/(x-5))?