How do you solve $x^4-x^2+9<=0$ ?

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Answer 1 · 2016-07-19T04:43:24

The Soln. does not exist, or,

The Soln. Set is $phi$ .

Given, $x^4=x^2<=-9$

Completing the square on $L.H.S., x^4-x^2+1/4<=-9+1/4$ , i.e.,

$(x^2-1/2)^2<=-35/4<0$ , or,

$(x^2-1/2)^2<0$ , which is impossible in $RR$

Hence, the Soln. does not exist, or, in other words,

The Soln. Set is $phi$ .

How do you solve x^4-x^2+9<=0x^4-x^2+9<=0?