How do you solve $(x-6)(x+10)<0$ ?

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Answer 1 · 2016-09-13T13:00:05

Solution is $-10 < x < 6$ .

As $(x-6)(x+10)<0$ , $(x-6)(x+10)$ is negative.

Hence,

either $(x-6)<0$ and $(x+10)>0$ i.e. $x<6$ and $x> -10$

which is true only if $-10 < x < 6$

or $(x-6)>0$ and $(x+10)<0$ i.e. $x>6$ and $x< -10$ , which cannot be true

Hence solution is $-10 < x < 6$ .

How do you solve (x-6)(x+10)<0(x-6)(x+10)<0?