How do you solve $y = 3 x + 1$ $y=3x+1$ and $y = 5 x - 3$ $y=5x-3$ ?

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Answer 1 · 2018-04-08T22:15:27

$(2, 7)$ $(2, 7)$
$x = 2$ $x=2$
$y = 7$ $y=7$

Set the equations equal to one another (they both equal y):

$3 x + 1 = 5 x - 3$ $3x+1=5x-3$

$3 x + 4 = 5 x$ $3x+4=5x$

$4 = 2 x$ $4=2x$

$x = 2$ $x=2$

Now plug 2 in for x and solve for y:

$y = 3 \cdot 2 + 1$ $y=3*2+1$

$y = 6 + 1$ $y=6+1$

$y = 7$ $y=7$

$y = 5 \cdot 2 - 3$ $y=5*2-3$

$y = 10 - 3$ $y=10-3$

$y = 7$ $y=7$

How do you solve y=3x+1y=3x+1y=3x+1 and y=5x-3y=5x−3y=5x-3?