How do you verify (1+tanx)/(1-tanx) = (cosx+sinx)/(cosx-sinx)?
1 Answer
Mar 9, 2016
see explanation
Explanation:
manipulate the left side
rArr (1+tanx)/(1-tanx) = (1+sinx/cosx)/(1-sinx/cosx) rewrite numerator / denominator as single fractions.
=((cosx+sinx)/cosx)/((cosx-sinx)/(cosx) multiply the fractions by ' inverting' the fraction on denominator.
rArr (cosx+sinx)/cancel(cosx) xx (cancel(cosx))/(cosx-sinx)
= (cosx+sinx)/(cosx-sinx) = " right side "