Question

How do you verify `cosBcotB=cscB-sinB`?

Answer 1

see below

Explanation:

`cosBcotB=cscB-sinB`

Right Side:`=cscB-sinB`

`=1/sinB -sinB`

`=(1 -sin^2B)/sinB`

`=cos^2B/sinB`

`=cosB*cosB/sinB`

`=cosBcotB`

`:.=`Left Side