How do you verify $cosy/(1-siny)=(1+siny)/cosy$ ?

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Answer 1 · 2016-11-21T19:31:54

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$cos y/(1-siny)=(1+siny)/cosy$

Left Side : $=cos y/(1-siny)$

$=cos y/(1-siny) * (1+siny)/(1+siny)$ --> multiply by conjugate

$= (cos y(1+siny))/(1-sin^2y)$

$= (cos y(1+siny))/cos^2y$

$= (cancelcos y(1+siny))/cos^cancel 2y$

$=(1+siny)/cosy$

$:.=$ Right Side

How do you verify cosy/(1-siny)=(1+siny)/cosycosy/(1-siny)=(1+siny)/cosy?