How do you verify $csc2(theta)=csc(theta)/(2cos(theta))$ ?

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Answer 1 · 2016-04-16T23:13:10

See below

LHS =left hand side, RHS =right hand side

LHS $=1/(sin (2 theta))$

$=1/(2sinthetacostheta)$

$=1/(2costheta) * 1/sin theta$

$=1/(2costheta) csc theta$

$=csc theta/(2cos theta)$

$=RHS$

How do you verify csc2(theta)=csc(theta)/(2cos(theta))csc2(theta)=csc(theta)/(2cos(theta))?