How do you verify (sin^2x - cos^2x)/(sinx + cosx)=sinx-cosx?
1 Answer
Apr 17, 2018
Explanation:
"consider the left side"
sin^2x-cos^2x" is a "color(blue)"difference of squares"
"which factorises, in general"
•color(white)(x)a^2-b^2=(a-b)(a+b)
rArr(sin^2x-cos^2x)/(sinx+cosx)
=((sinx-cosx)cancel((sinx+cosx)))/cancel((sinx+cosx))
=sinx-cosx="right side "rArr"verified"