How do you verify (sin^2x - cos^2x)/(sinx + cosx)=sinx-cosx?

1 Answer
Apr 17, 2018

"see explanation"

Explanation:

"consider the left side"

sin^2x-cos^2x" is a "color(blue)"difference of squares"

"which factorises, in general"

•color(white)(x)a^2-b^2=(a-b)(a+b)

rArr(sin^2x-cos^2x)/(sinx+cosx)

=((sinx-cosx)cancel((sinx+cosx)))/cancel((sinx+cosx))

=sinx-cosx="right side "rArr"verified"