How do you verify sin^5xcos^2x=(cos^2x-2cos^4x+cos^6x)sinx?

1 Answer
Cesareo R.
Jul 3, 2016

See below

Explanation:

Operating in both sides

sin^5xcos^2x=(cos^2x-2cos^4x+cos^6x)sinx
sin xsin^4xcos^2x=(cos^2x-2cos^4x+cos^6x)sin x
sin xsin^4xcos^2x=(1-2cos^2x+cos^4x)cos^2x sin x
sin xsin^4xcos^2x=(1-cos^2x)^2cos^2x sin x
sin xsin^4xcos^2x=sin^4xcos^2x sin x

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