How do you verify $tan^2(a) - sin^2(a)=tan^2(a)sin^2(a)$ ?

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Answer 1 · 2016-04-17T02:36:40

See below

Left Side $=sin^2a/cos^2a - sin^2a$

$=(sin^2a-sin^2acos^2a)/cos^2a$

$=(sin ^2a(1-cos^2a))/cos ^2a$

$=(sin ^2a xx sin^2a)/cos^2a$

$=sin^2a/cos^2a xx sin^2a$

$=tan^2a sin^2a$

$=$ Right side

How do you verify tan^2(a) - sin^2(a)=tan^2(a)sin^2(a) tan^2(a) - sin^2(a)=tan^2(a)sin^2(a)?