How do you write 2(x+4)^2 + 3(y-1)^2 = 24 in standard form?

1 Answer
May 3, 2016

(x-(-4))^2/(sqrt(12))^2 +(y-1)^2/(sqrt(8))^2=1

Explanation:

The standard form for an ellipse is
color(white)("XXX")(x-h)^2/a^2+(y-k)^2/b^2=1

Given
color(white)("XXX")2(x+4)^2+3(y-1)^2=24

rArr
color(white)("XXX")(x+4)^2/12+(y-1)^2/8=1

color(white)("XXX")(x-(-4))^2/(sqrt(12))^2+(y-1)^2/(sqrt(8))^2=1

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If you like you could replace (sqrt(12))^2 with (2sqrt(3))^2
and (sqrt(8))^2 with (2sqrt(2))^2
...but this really doesn't make the form any simpler.