How do you write #35times24times23times 22times 4times3times2times1# as a ratio of factorials?

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Answer 1 · 2015-11-14T00:29:04

#((35!)(24!)(4!))/((34!)(21!))# or #((23!)(11!)(8!))/((22!)(10!))#

#35xx24xx23xx22xx4xx3xx2xx1#

#=(35!)/(34!)xx(24!)/(21!)xx(4!)=((35!)(24!)(4!))/((34!)(21!))#

or

#35xx24xx23xx22xx4xx3xx2xx1#

#=5xx7xx8xx3xx23xx2xx11xx4xx3xx2xx1#

#=23xx11xx8xx7xx6xx5xx4xx3xx2xx1#

#=(23!)/(22!)xx(11!)/(10!)xx(8!)=((23!)(11!)(8!))/((22!)(10!))#