How do you write #3x - 2y= 5 # into slope intercept form?
1 Answer
Aug 22, 2015
Explanation:
For a general line
#color(blue)(y = mx + b)" "# , where
So basically, all you have to do to write the equation for your line in sloper-intercept form is isolate
Start by adding
#-color(red)(cancel(color(black)(3x))) + color(red)(cancel(color(black)(3x))) - 2y = 5 - 3x#
#-2y = -3x + 5#
Now divide both sides of the equation by
#(color(red)(cancel(color(black)(-2))) * y)/color(red)(cancel(color(black)(-2))) = ((-3))/((-2))x + 5/((-2))#
#color(green)(y = 3/2x - 5/2)#