How do you write 3X=4-3X^2 in vertex form?

1 Answer
Jun 28, 2017

3(x+1/2)^2-19/4

Explanation:

"the equation of a parabola in "color(blue)"vertex form" is.

color(red)(bar(ul(color(white)(2/2)color(black)(y=a(x-h)^2+k)color(white)(2/2)|)))
where ( h , k ) are the coordinates of the vertex and a is a constant.

"the equation of a parabola in standard form " ax^2+bx+c

"has the x-coordinate of the vertex at " x_(color(red)"vertex")=-b/(2a)

"rearrange " 3x=4-3x^2" into this form"

rArr3x^2+3x-4rArry=3x^2+3x-4

"with " a=3,b=3" and " c=-4

rArrx_(color(red)"vertex")=-3/(6)=-1/2

"substitute this value into the standard form for y"

rArry_(color(red)"vertex")=3(-1/2)^2+3(1/2)-4=-19/4

rArrcolor(magenta)"vertex "=(-1/2,-19/4)

rArry=3(x+1/2)^2-19/4larrcolor(red)" in vertex form"