How do you write #-4/9+2/9y=x# in standard form?
1 Answer
Our goal is to isolate Y.
First step: move the minus four ninths to the other side, so that you'll have:
(2/9)y = x + (4/9)
Note that as we pass an element adding from one side to the other, it goes from positive to negative and vice-versa for subtracting elements.
Second step: 2 is multiplying Y. We need to move it to the other side. As we change the operations to their inverse form (to preserve equality), this little boy number 2 goes to the other side dividing BOTH elements. Now, we'll have:
y/9 = x/2 + (4/18)
Note that as we divide 4/9 by 2, it becomes 4/18 because in the lower part of the fraction we'll have a multiplication: 9 times 2 = 18.
Third step: Now, we need to get the 9 that's dividing Y to the other side. Simple. On the other side, it will multiply BOTH elements, as follows:
y = (9x/2) + (36/18)
Or you can simplify the (36/18) dividing both upper and lower parts by 9, getting a new (4/2), which can be easily simplified to 2.
So:
y = (9x/2) + 2
If you want to be somewhat of a perfectionist, you can even divide 9 by 2 and stop to work with fractions. Like this:
Y = 4.5x + 2
Up to you, now: do you feel more comfortable with fractions or decimal numbers?
Cheers!