How do you write $4x^2-12x+7$ into vertex form?

Question

5309 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-05-03T19:58:05

In vertex form
$y = m(x-a)^2+b$
where $(a,b)$ is the vertex of the quadratic.

$y=4x^2-12x+7$

$y = 4(x^2-3x)+7 " extract "m$

$y=4(x^2-3x+(3/2)^2) -9+7 " complete the square"$

$y=4(x-3/2)^2- (-2)$

and the vertex is at $(3/2,-2)$

How do you write 4x^2-12x+74x^2-12x+7 into vertex form?