How do you write #4x^2 + 20x - 4y^2 + 6y - 3 = 0# in standard form?

Question

↳Redirected from "What did Rutherford's gold foil show about the structure of an atom?"

1540 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-10T15:03:19

#(x+5/2)^2-(y-3/4)^2=[121]/[16]#

#4x^2+20x-4y^2+6y=3#

Divide by 4

#x^2+5x-y^2+3/2y=3/4#

Complete the square

#(x+5/2)^2-25/4-(y-3/4)^2-9/[16]=3/4#

#(x+5/2)^2-(y-3/4)^2=3/4+[109]/[16]#

#(x+5/2)^2-(y-3/4)^2=[121]/[16]#