How do you write $4x^2-4x+2$ in vertex form?

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Answer 1 · 2015-05-21T11:44:40

Given $y=4x^2-4x+2$

The general vertex form is
$y = m(x-a)^2+b$ where $(a,b)$ is the vertex of the parabola

Extract $m$
$y=4(x^2-x) +2$

Complete the square
$y= 4(x^2-x+1/4) +2 +1$

Rewrite in vertex form
$y=4(x-1/2)+3$

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