How do you write #5/6x+1/10y=3/10# in standard form and what is A, B, C?

1 Answer
Aug 10, 2017

See a solution process below:

Explanation:

The standard form of a linear equation is: #color(red)(A)x + color(blue)(B)y = color(green)(C)#

Where, if at all possible, #color(red)(A)#, #color(blue)(B)#, and #color(green)(C)#are integers, and A is non-negative, and, A, B, and C have no common factors other than 1

We can multiply each side of the equation by #color(red)(30)# to eliminate the fractions and ensure the coefficients are integers while keeping the equation balanced:

#color(red)(30)(5/6x + 1/10y) = color(red)(30) xx 3/10#

#(color(red)(30) xx 5/6x) + (color(red)(30) xx 1/10y) = 90/10#

#(150x)/6 + (30y)/10 = 9#

#color(red)(25)x + color(blue)(3)y = color(green)(9)#

#color(red)(A = 25)#

#color(blue)(B = 3)#

#color(green)(C = 9)#