How do you write 5x-4y=8 in slope intercept form?

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Answer 1 · 2018-04-07T14:18:00

$- y = - \frac{5}{4} x + 2$ $-y = -5/4x + 2$

$y = m x + b$ $y = mx + b$

$m = slope$ $"m = slope"$
$b = y-intercept$ $"b = y-intercept"$

So we'll just rearrange your current equation to be in slope-intercept form.

$5 x - 4 y = 8$ $5x-4y=8$

$- 4 y = - 5 x + 8$ $-4y = - 5x + 8$

$- y = - \frac{5}{4} x + 2$ $-y = -5/4x + 2$

Now I'm going to multiply the whole equation by $- 1$ $-1$ , because I don't want $y$ $y$ to be negative. This will change the sign of all the parts.

$y = \frac{5}{4} x - 2$ $y = 5/4x - 2$

graph{y = 5/4x - 2 [-12.66, 12.65, -6.33, 6.33]}