How do you write #60# using factorials?
1 Answer
Feb 3, 2016
Explanation:
First, try to find a series of consecutive integers whose product is
#60=2^2xx3xx5=5xx4xx3#
Note that
#60=5xx4xx3=(5xx4xx3xx2xx1)/(2xx1)=(5!)/(2!)#
This is the simplest way to express
#60=10xx6=(10!)/(9!)xx(6!)/(5!)=((10!)(6!))/((9!)(5!))#