Question

How do you write a polynomial in standard form given zeros 3, 2, -1?

Answer 1

`x^3-4x^2+x+6`

Explanation:

Using the fact that if `(x-a)` is a factor of a polynomial, then `a` is a root of that polynomial, we can generate a polynomial with a given set of roots easily by starting from its factored form.

In this case, given the roots `3`, `2`, and `-1`, we would have

`P(x) = (x-3)(x-2)(x-(-1)) = x^3-4x^2+x+6`