How do you write a quadratic function in intercept form whose graph has x intercepts -3, -2 and passes through (-4, -6)?

1 Answer
Jul 25, 2017

The quadratic equation in intercept form is y=-3(x+3)(x+2)y=3(x+3)(x+2).

Explanation:

The quadratic equation in intercept form is y=a(x-p)(x-q)y=a(xp)(xq)

where p=-3 and q=-2p=3andq=2 are x -intercepts . So The quadratic

equation in intercept form is y=a(x+3)(x+2)y=a(x+3)(x+2). The parabola

passes through (-4,-6)(4,6) , which will satisfy the equation of

parabola. :. -6 = a ( -4+3)(-4+2) or -6 = 2a or

a = -3 . Hence the quadratic equation in intercept form is

y=-3(x+3)(x+2).

graph{-3(x+3)(x+2) [-10, 10, -5, 5]} [Ans]