How do you write a quadratic function in intercept form whose graph has x intercepts -3, -2 and passes through (-4, -6)?

Question

9690 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-07-25T12:08:36

The quadratic equation in intercept form is $y = - 3 (x + 3) (x + 2)$ $y=-3(x+3)(x+2)$ .

The quadratic equation in intercept form is $y = a (x - p) (x - q)$ $y=a(x-p)(x-q)$

where $p = - 3 and q = - 2$ $p=-3 and q=-2$ are x -intercepts . So The quadratic

equation in intercept form is $y = a (x + 3) (x + 2)$ $y=a(x+3)(x+2)$ . The parabola

passes through $(- 4, - 6)$ $(-4,-6)$ , which will satisfy the equation of

parabola. $:. -6 = a ( -4+3)(-4+2) or -6 = 2a$ or

$a = -3$ . Hence the quadratic equation in intercept form is

$y=-3(x+3)(x+2)$ .

graph{-3(x+3)(x+2) [-10, 10, -5, 5]} [Ans]