Question

How do you write an equation with Vertex (-3, 12), point (-1, 0) on quadratic?

Answer 1

`y=-3(x+3)^2+12`

Explanation:

`"the equation of a parabola in "color(blue)"vertex form"` is.

`color(red)(bar(ul(|color(white)(2/2)color(black)(y=a(x-h)^2+k)color(white)(2/2)|)))`
where (h , k ) are the coordinates of the vertex and a is a constant.

`"here "(h,k)=(-3,12)`

`rArry=a(x+3)^2+12`

`"to find a substitute "(-1,0)" into the equation"`

`0=4a+12rArra=-3`

`rArry=-3(x+3)^2+12larrcolor(red)" in vertex form"`