How do you write $f (x) = 2 x^{2} + 8 x + 7$ $f(x)=2x^2+8x+7$ in vertex form?

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How do you write $f (x) = 2 x^{2} + 8 x + 7$ $f(x)=2x^2+8x+7$ in vertex form?

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Answer 1 · 2016-07-09T02:08:32

$f (x) = 2 {(x + 2)}^{2} - 1$ $f(x) = 2(x + 2)^2 - 1$

Explanation:

x-coordinate of vertex:
$x = - \frac{b}{2 a} = - \frac{8}{4} = - 2$ $x = -b/(2a) = -8/4 = -2$
y-coordinate of vertex:
$f (- 2) = 8 - 16 + 7 = - 1$ $f(-2) = 8 - 16 + 7 = - 1$
Vertex (-2, -1)
Vertex form of y:
$f (x) = 2 {(x + 2)}^{2} - 1$ $f(x) = 2(x + 2)^2 - 1$

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How do you write $f (x) = 2 x^{2} + 8 x + 7$ $f(x)=2x^2+8x+7$ in vertex form?

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Explanation:

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How do you write $f (x) = 2 x^{2} + 8 x + 7$ $f(x)=2x^2+8x+7$ in vertex form?